C program which inputs n and r and computes nCr ie nCr = n! / r! (n-r)!

Write a program which inputs n and r and computes nCr by calling the

function which returns the factorial of its argument. The function computes

the factorial by using recursive method.

nCr = n! / r! (n-r)!

#include<stdio .h="">

#include<conio .h="">

float nfac(float);

float rfac(float);

float n_rfac(float);

void main()

{

float n,r,n_r,fn=1,fr=1,fn_r=1,ncr;

clrscr();

printf("Enter n");

scanf("%f",&amp;n);

printf("Enter r");

scanf("%f",&amp;r);

n_r=n-r;

fn=nfac(n);

fr=rfac(r);

fn_r=n_rfac(n_r);

ncr=fn/(fr*fn_r);

printf("\n%.0fC%.0f=%.0f!/(%.0f!*%.0f!)",n,r,n,r,n_r);

printf("\n==&gt; %.0f / (%.0f * %.0f)",fn,fr,fn_r);

printf("\n==&gt;nCr=%f",ncr);

getch();

}

float nfac(float n)

 {

 float i,fcn=1;

 for(i=1;i&lt;=n;i++)

  fcn*=i;

 return(fcn);

 }

float rfac(float r)

 {

 float i,fcr=1;

 for(i=1;i&lt;=r;i++)

  fcr*=i;

 return(fcr);

 }

float n_rfac(float n_r)

 {

 float i,fcn_r=1;

 for(i=1;i&lt;=n_r;i++)

  fcn_r*=i;

 return(fcn_r);

 }

/* Output

Enter n3

Enter r3

3C3=3!/(3!*0!)

==&gt; 6 / (6 * 1)

==&gt;nCr=1.000000

*/</conio></stdio>